A metal rod 2.00 m long and 1.00 cm2 in cross-section is
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A metal rod 2.00 m long and 1.00 cm2 in cross-section is
subjected to a tensile force of 5.00 kN.As a result its
length increases by 0.800 mm.Calculate Young’s modulus
for the material from which the rod is made.
求杨氏模量的～
25X10^11Nm^-2
为什么还要在这两个量之间除一下呢？
优质解答：
[5000N/1.0*10^(-4)m^2]/[0.8*10^(-6)m/2.00m]=1.25X10^11Nm^-2