分解因式1.-a^mb^2m+1+a^m+1b^2m 2.3ax^m+1-5ax^m+3ax^m-1 3.12x^2n+

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分解因式1.-a^mb^2m+1+a^m+1b^2m 2.3ax^m+1-5ax^m+3ax^m-1 3.12x^2n+1y^m+2-20x^n+1y^2m+3

分解因式1.-a^mb^2m+1+a^m+1b^2m

2.3ax^m+1-5ax^m+3ax^m-1

3.12x^2n+1y^m+2-20x^n+1y^2m+3

分解因式1.-a^mb^2m+1+a^m+1b^2m

2.3ax^m+1-5ax^m+3ax^m-1

3.12x^2n+1y^m+2-20x^n+1y^2m+3分解因式1.-a^mb^2m+1+a^m+1b^2m

2.3ax^m+1-5ax^m+3ax^m-1

3.12x^2n+1y^m+2-20x^n+1y^2m+3

分解因式1.-a^mb^2m+1+a^m+1b^2m

2.3ax^m+1-5ax^m+3ax^m-1

3.12x^2n+1y^m+2-20x^n+1y^2m+3

优质解答：

1.-a^mb^(2m+1)+a^(m+1)b^2m

=a^(m+1)b^2m-a^mb^(2m+1)

=a*a^mb^2m-a^mb^2m*b

=a^mb^2m(a-b)

2.3ax^(m+1)-5ax^m+3ax^(m-1)

=3a*x^2*x^(m-1)-5a*x*x^(m-1)+3ax^(m-1)

=ax^(m-1)(3x^2-5x+3)

3.12x^(2n+1)y^(m+2)-20x^(n+1)y^(2m+3)

=12x^(n+1)*x^ny^(m+2)-20x^(n+1)y^(m+2)*y^(m+1)

=4x^(n+1)y^(m+2)[3x^n-5y^(m+1)]

再问： 对不对啊- -感觉你的好像搞错了把=a^(m+1)b^2m-a^mb^(2m+1) 错了把，b的2m次-amb次的2m+1次？

我来回答修改/报错/举报内容！

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